10x^2+4.9=11.3

Solution for 10x^2+4.9=11.3 equation:

10x^2+4.9=11.3

We move all terms to the left:

10x^2+4.9-(11.3)=0

We add all the numbers together, and all the variables

10x^2-6.4=0

a = 10; b = 0; c = -6.4;
Δ = b2-4ac
Δ = 02-4·10·(-6.4)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*10}=\frac{-16}{20}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*10}=\frac{16}{20}
=4/5
$